The distance between the two inner parallel line segments is 60 m and they are each 106 m long. The given figure depicts a racing track whose left and right ends are semicircular. Find the area of the shaded region.Īrea of the squat e = (side)² = 14 x 14 = 196² With centres A, B, C and D, four circles are drawn such that each circle touch externally two of the remaining three circles.

In the figure, ABCD is a square of side 14 cm.

∴ An equilateral triangle is formed in the circle as shown Find the area of the design (shaded region). In a circular table cover of the radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in the figure. See also NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.5 ∴ Area of the remaining portion = Area of the square – Area to be cut from square Find the area of the remaining portion of the square. Total area of both the semicircles = 77 + 77 = 154 cm²Īrea of the shaded region = Area of square – area of both semicirclesįind the area of the shaded region in the figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre.įrom each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in the figure. Similarly, area of the semicircle BPC = 77 cm² Radius of the semicircle APD = 1 2(side of square) = 1 2 x 14 = 7 cmĪrea of the semicircle APD = 1 2 πr² = 1 2 × 22 7 × 7 × 7 = 11 × 7 = 77cm² NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Ex 12.3įind the area of the shaded region in the given figure, if PQ = 24cm, PR = 7cm and O is the centre of the circle.įind the area of the shaded region in the given figure, if radii of the two concentric circles with centre O are 7 cm and 14 cm respectively and ∠AOC = 400.įind the area of the shaded region in the given figure, if ABCD is a square of side 14 cm and APD and BPC are semicircles.

Ex 12.3 class 10